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LTC1430A Просмотр технического описания (PDF) - Linear Technology

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LTC1430A Datasheet PDF : 24 Pages
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LTC1430A
APPLICATI S I FOR ATIO
scheme. In 5V input designs where an auxiliary 12V supply
is available to power PVCC1 and PVCC2, standard MOSFETs
with RDS(ON) specified at VGS = 5V or 6V can be used with
good results. The current drawn from this supply varies
with the MOSFETs used and the LTC1430A’s operating
frequency, but is generally less than 50mA.
LTC1430A designs that use a doubler charge pump to
generate gate drive for Q1 and run from PVCC voltages
below 7V cannot provide enough gate drive voltage to fully
enhance standard power MOSFETs. When run from 5V, a
doubler circuit may work with standard MOSFETs, but the
MOSFET RON may be quite high, raising the dissipation in
the FETs and costing efficiency. Logic level FETs are a
better choice for 5V PVCC systems; they can be fully
enhanced with a doubler charge pump and will operate at
maximum efficiency. Doubler designs running from PVCC
voltages near 4V will begin to run into efficiency problems
even with logic level FETs; such designs should be built
with tripler charge pumps (see Figure 7) or with newer,
super low threshold MOSFETs. Note that doubler charge
pump designs running from more than 7V and all tripler
charge pump designs should include a zener clamp diode
DZ at PVCC1 to prevent transients from exceeding the
absolute maximum rating at that pin.
Once the threshold voltage has been selected, RON should
be chosen based on input and output voltage, allowable
power dissipation and maximum required output current.
In a typical LTC1430A buck converter circuit operating in
continuous mode, the average inductor current is equal to
DZ
12V
1N5242
1N5817
1N5817
PVCC
1N5817
10µF
PVCC2
PVCC1
G1
G2
LTC1430A
0.1µF
0.1µF
Q1
L1
Q2
VOUT
+
COUT
1430 • F07
Figure 7. Tripling Charge Pump
the output load current. This current is always flowing
through either Q1 or Q2 with the power dissipation split up
according to the duty cycle:
DC (Q1) =
VOUT
VIN
DC
(Q2)
=
1
VOUT
VIN
= (VIN – VOUT)
VIN
The RON required for a given conduction loss can now be
calculated by rearranging the relation P = I2R:
RON
(Q1)
=
PMAX(Q1)
DC(Q1)(IMAX2)
=
VIN(PMAX)(Q1)
VOUT(IMAX2)
RON
(Q2)
=
PMAX(Q2)
DC(Q2)(IMAX2)
=
VIN(PMAX)(Q2)
(VIN – VOUT)(IMAX2)
PMAX should be calculated based primarily on required
efficiency. A typical high efficiency circuit designed for 5V
in, 3.3V at 10A out might require no more than 3%
efficiency loss at full load for each MOSFET. Assuming
roughly 90% efficiency at this current level, this gives a
PMAX value of (3.3V)(10A/0.9)(0.03) = 1.1W per FET and
a required RON of:
RON
(Q1)
=
(5V)(1.1W)
(3.3V)(10A2)
=
0.017
RON
(Q2)
=
(5V)(1.1W)
(5V – 3.3V)(10A2)
=
0.032
Note that the required RON for Q2 is roughly twice that of
Q1 in this example. This application might specify a single
0.03device for Q2 and parallel two more of the same
devices to form Q1. Note also that while the required RON
values suggest large MOSFETs, the dissipation numbers
10

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