HCPL-3150-XXXE Просмотр технического описания (PDF) - HP => Agilent Technologies

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HCPL-3150-XXXE

High CMR/ High Speed TTL Compatible Optocouplers

HP => Agilent Technologies 

14

+5 V

1

CONTROL

270 Ω

INPUT

2

74XX

OPEN

COLLECTOR

3

GND 1

+5 V

6

270 Ω

CONTROL

INPUT

7

74XX

OPEN

COLLECTOR

8

GND 1

HCPL-315J

16

0.1 µF

15

14

FLOATING

SUPPLY

VCC = 18 V

+

–

Rg

11

0.1 µF

10

9

VCC = 18 V

+

–

Rg

Figure 25b. Recommended LED Drive and Application Circuit (HCPL-315J).

+ HVDC

3-PHASE

AC

- HVDC

Selecting the Gate Resistor

(Rg) to Minimize IGBT

Switching Losses.

Step 1: Calculate Rg Minimum

From the IOL Peak Specifica-

tion. The IGBT and Rg in Figure

26 can be analyzed as a simple

RC circuit with a voltage supplied

by the HCPL-3150/315J.

Rg ≥ (–V–C–C–––I–O–VL–EPE–EA–-K–V–O––L)–

= (–V–C–C–––I–O–VL–EPE–EA–-K–1––.7––V–)

= (–1––5–V0––.+6––A5––V––-–1–.–7––V–)

= 30.5 Ω

The VOL value of 2 V in the pre-

vious equation is a conservative

value of VOL at the peak current

of 0.6 A (see Figure 6). At lower

Rg values the voltage supplied by

the HCPL-3150/315J is not an

ideal voltage step. This results in

lower peak currents (more

margin) than predicted by this

analysis. When negative gate

drive is not used VEE in the

previous equation is equal to zero

volts.

Step 2: Check the HCPL-3150/

315J Power Dissipation and

Increase Rg if Necessary. The

HCPL-3150/315J total power

dissipation (PT) is equal to the

sum of the emitter power (PE) and

the output power (PO):

PT = PE + PO

PE = IF • VF • Duty Cycle

PO = PO(BIAS) + PO (SWITCHING)

= ICC•(VCC - VEE)

+ ESW(RG, QG) •f

For the circuit in Figure 26 with IF

(worst case) = 16 mA, Rg =

30.5 Ω, Max Duty Cycle = 80%,

Qg = 500 nC, f = 20 kHz and TA

max = 90°C:

PE = 16 mA•1.8 V •0.8 = 23 mW

PO = 4.25 mA •20 V

+ 4.0 µJ•20 kHz

= 85 mW + 80 mW

= 165 mW

> 154 mW (PO(MAX) @ 90°C

= 250 mW−20C•4.8 mW/C)

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